3.1.62 \(\int \frac {\sqrt {\pi +c^2 \pi x^2} (a+b \sinh ^{-1}(c x))}{x^4} \, dx\) [62]

Optimal. Leaf size=62 \[ -\frac {b c \sqrt {\pi }}{6 x^2}-\frac {\left (\pi +c^2 \pi x^2\right )^{3/2} \left (a+b \sinh ^{-1}(c x)\right )}{3 \pi x^3}+\frac {1}{3} b c^3 \sqrt {\pi } \log (x) \]

[Out]

-1/3*(Pi*c^2*x^2+Pi)^(3/2)*(a+b*arcsinh(c*x))/Pi/x^3-1/6*b*c*Pi^(1/2)/x^2+1/3*b*c^3*ln(x)*Pi^(1/2)

________________________________________________________________________________________

Rubi [A]
time = 0.06, antiderivative size = 62, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.077, Rules used = {5800, 14} \begin {gather*} -\frac {\left (\pi c^2 x^2+\pi \right )^{3/2} \left (a+b \sinh ^{-1}(c x)\right )}{3 \pi x^3}+\frac {1}{3} \sqrt {\pi } b c^3 \log (x)-\frac {\sqrt {\pi } b c}{6 x^2} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(Sqrt[Pi + c^2*Pi*x^2]*(a + b*ArcSinh[c*x]))/x^4,x]

[Out]

-1/6*(b*c*Sqrt[Pi])/x^2 - ((Pi + c^2*Pi*x^2)^(3/2)*(a + b*ArcSinh[c*x]))/(3*Pi*x^3) + (b*c^3*Sqrt[Pi]*Log[x])/
3

Rule 14

Int[(u_)*((c_.)*(x_))^(m_.), x_Symbol] :> Int[ExpandIntegrand[(c*x)^m*u, x], x] /; FreeQ[{c, m}, x] && SumQ[u]
 &&  !LinearQ[u, x] &&  !MatchQ[u, (a_) + (b_.)*(v_) /; FreeQ[{a, b}, x] && InverseFunctionQ[v]]

Rule 5800

Int[((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))^(n_.)*((f_.)*(x_))^(m_)*((d_) + (e_.)*(x_)^2)^(p_), x_Symbol] :> Simp[
(f*x)^(m + 1)*(d + e*x^2)^(p + 1)*((a + b*ArcSinh[c*x])^n/(d*f*(m + 1))), x] - Dist[b*c*(n/(f*(m + 1)))*Simp[(
d + e*x^2)^p/(1 + c^2*x^2)^p], Int[(f*x)^(m + 1)*(1 + c^2*x^2)^(p + 1/2)*(a + b*ArcSinh[c*x])^(n - 1), x], x]
/; FreeQ[{a, b, c, d, e, f, m, p}, x] && EqQ[e, c^2*d] && GtQ[n, 0] && EqQ[m + 2*p + 3, 0] && NeQ[m, -1]

Rubi steps

\begin {align*} \int \frac {\sqrt {\pi +c^2 \pi x^2} \left (a+b \sinh ^{-1}(c x)\right )}{x^4} \, dx &=-\frac {\left (\pi +c^2 \pi x^2\right )^{3/2} \left (a+b \sinh ^{-1}(c x)\right )}{3 \pi x^3}+\frac {\left (b c \sqrt {\pi +c^2 \pi x^2}\right ) \int \frac {1+c^2 x^2}{x^3} \, dx}{3 \sqrt {1+c^2 x^2}}\\ &=-\frac {\left (\pi +c^2 \pi x^2\right )^{3/2} \left (a+b \sinh ^{-1}(c x)\right )}{3 \pi x^3}+\frac {\left (b c \sqrt {\pi +c^2 \pi x^2}\right ) \int \left (\frac {1}{x^3}+\frac {c^2}{x}\right ) \, dx}{3 \sqrt {1+c^2 x^2}}\\ &=-\frac {b c \sqrt {\pi +c^2 \pi x^2}}{6 x^2 \sqrt {1+c^2 x^2}}-\frac {\left (\pi +c^2 \pi x^2\right )^{3/2} \left (a+b \sinh ^{-1}(c x)\right )}{3 \pi x^3}+\frac {b c^3 \sqrt {\pi +c^2 \pi x^2} \log (x)}{3 \sqrt {1+c^2 x^2}}\\ \end {align*}

________________________________________________________________________________________

Mathematica [A]
time = 0.08, size = 78, normalized size = 1.26 \begin {gather*} -\frac {\sqrt {\pi } \left (b c x+3 b c^3 x^3+2 a \left (1+c^2 x^2\right )^{3/2}+2 b \left (1+c^2 x^2\right )^{3/2} \sinh ^{-1}(c x)\right )}{6 x^3}+\frac {1}{3} b c^3 \sqrt {\pi } \log (x) \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(Sqrt[Pi + c^2*Pi*x^2]*(a + b*ArcSinh[c*x]))/x^4,x]

[Out]

-1/6*(Sqrt[Pi]*(b*c*x + 3*b*c^3*x^3 + 2*a*(1 + c^2*x^2)^(3/2) + 2*b*(1 + c^2*x^2)^(3/2)*ArcSinh[c*x]))/x^3 + (
b*c^3*Sqrt[Pi]*Log[x])/3

________________________________________________________________________________________

Maple [B] Leaf count of result is larger than twice the leaf count of optimal. \(500\) vs. \(2(50)=100\).
time = 6.54, size = 501, normalized size = 8.08

method result size
default \(-\frac {a \left (\pi \,c^{2} x^{2}+\pi \right )^{\frac {3}{2}}}{3 \pi \,x^{3}}-\frac {2 b \,c^{3} \sqrt {\pi }\, \arcsinh \left (c x \right )}{3}+\frac {b \sqrt {\pi }\, x^{4} \arcsinh \left (c x \right ) c^{7}}{3 c^{4} x^{4}+3 c^{2} x^{2}+1}-\frac {b \sqrt {\pi }\, x^{3} \arcsinh \left (c x \right ) \sqrt {c^{2} x^{2}+1}\, c^{6}}{3 c^{4} x^{4}+3 c^{2} x^{2}+1}+\frac {b \sqrt {\pi }\, x^{4} c^{7}}{18 c^{4} x^{4}+18 c^{2} x^{2}+6}-\frac {b \sqrt {\pi }\, x^{2} \left (c^{2} x^{2}+1\right ) c^{5}}{6 \left (3 c^{4} x^{4}+3 c^{2} x^{2}+1\right )}+\frac {b \sqrt {\pi }\, x^{2} \arcsinh \left (c x \right ) c^{5}}{3 c^{4} x^{4}+3 c^{2} x^{2}+1}-\frac {2 b \sqrt {\pi }\, x \arcsinh \left (c x \right ) \sqrt {c^{2} x^{2}+1}\, c^{4}}{3 c^{4} x^{4}+3 c^{2} x^{2}+1}-\frac {b \sqrt {\pi }\, \left (c^{2} x^{2}+1\right ) c^{3}}{3 \left (3 c^{4} x^{4}+3 c^{2} x^{2}+1\right )}+\frac {b \,c^{3} \sqrt {\pi }\, \arcsinh \left (c x \right )}{9 c^{4} x^{4}+9 c^{2} x^{2}+3}-\frac {4 b \sqrt {\pi }\, \arcsinh \left (c x \right ) \sqrt {c^{2} x^{2}+1}\, c^{2}}{3 \left (3 c^{4} x^{4}+3 c^{2} x^{2}+1\right ) x}-\frac {b \sqrt {\pi }\, \left (c^{2} x^{2}+1\right ) c}{6 \left (3 c^{4} x^{4}+3 c^{2} x^{2}+1\right ) x^{2}}-\frac {b \sqrt {\pi }\, \arcsinh \left (c x \right ) \sqrt {c^{2} x^{2}+1}}{3 \left (3 c^{4} x^{4}+3 c^{2} x^{2}+1\right ) x^{3}}+\frac {b \,c^{3} \sqrt {\pi }\, \ln \left (\left (c x +\sqrt {c^{2} x^{2}+1}\right )^{2}-1\right )}{3}\) \(501\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a+b*arcsinh(c*x))*(Pi*c^2*x^2+Pi)^(1/2)/x^4,x,method=_RETURNVERBOSE)

[Out]

-1/3*a/Pi/x^3*(Pi*c^2*x^2+Pi)^(3/2)-2/3*b*c^3*Pi^(1/2)*arcsinh(c*x)+b*Pi^(1/2)/(3*c^4*x^4+3*c^2*x^2+1)*x^4*arc
sinh(c*x)*c^7-b*Pi^(1/2)/(3*c^4*x^4+3*c^2*x^2+1)*x^3*arcsinh(c*x)*(c^2*x^2+1)^(1/2)*c^6+1/6*b*Pi^(1/2)/(3*c^4*
x^4+3*c^2*x^2+1)*x^4*c^7-1/6*b*Pi^(1/2)/(3*c^4*x^4+3*c^2*x^2+1)*x^2*(c^2*x^2+1)*c^5+b*Pi^(1/2)/(3*c^4*x^4+3*c^
2*x^2+1)*x^2*arcsinh(c*x)*c^5-2*b*Pi^(1/2)/(3*c^4*x^4+3*c^2*x^2+1)*x*arcsinh(c*x)*(c^2*x^2+1)^(1/2)*c^4-1/3*b*
Pi^(1/2)/(3*c^4*x^4+3*c^2*x^2+1)*(c^2*x^2+1)*c^3+1/3*b*Pi^(1/2)/(3*c^4*x^4+3*c^2*x^2+1)*arcsinh(c*x)*c^3-4/3*b
*Pi^(1/2)/(3*c^4*x^4+3*c^2*x^2+1)/x*arcsinh(c*x)*(c^2*x^2+1)^(1/2)*c^2-1/6*b*Pi^(1/2)/(3*c^4*x^4+3*c^2*x^2+1)/
x^2*(c^2*x^2+1)*c-1/3*b*Pi^(1/2)/(3*c^4*x^4+3*c^2*x^2+1)/x^3*arcsinh(c*x)*(c^2*x^2+1)^(1/2)+1/3*b*c^3*Pi^(1/2)
*ln((c*x+(c^2*x^2+1)^(1/2))^2-1)

________________________________________________________________________________________

Maxima [B] Leaf count of result is larger than twice the leaf count of optimal. 133 vs. \(2 (50) = 100\).
time = 0.28, size = 133, normalized size = 2.15 \begin {gather*} -\frac {{\left (\pi ^{\frac {3}{2}} \left (-1\right )^{2 \, \pi + 2 \, \pi c^{2} x^{2}} c^{2} \log \left (2 \, \pi c^{2} + \frac {2 \, \pi }{x^{2}}\right ) - \pi ^{\frac {3}{2}} c^{2} \log \left (x^{2} + \frac {1}{c^{2}}\right ) + \frac {\pi \sqrt {\pi + \pi c^{4} x^{4} + 2 \, \pi c^{2} x^{2}}}{x^{2}}\right )} b c}{6 \, \pi } - \frac {{\left (\pi + \pi c^{2} x^{2}\right )}^{\frac {3}{2}} b \operatorname {arsinh}\left (c x\right )}{3 \, \pi x^{3}} - \frac {{\left (\pi + \pi c^{2} x^{2}\right )}^{\frac {3}{2}} a}{3 \, \pi x^{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*arcsinh(c*x))*(pi*c^2*x^2+pi)^(1/2)/x^4,x, algorithm="maxima")

[Out]

-1/6*(pi^(3/2)*(-1)^(2*pi + 2*pi*c^2*x^2)*c^2*log(2*pi*c^2 + 2*pi/x^2) - pi^(3/2)*c^2*log(x^2 + 1/c^2) + pi*sq
rt(pi + pi*c^4*x^4 + 2*pi*c^2*x^2)/x^2)*b*c/pi - 1/3*(pi + pi*c^2*x^2)^(3/2)*b*arcsinh(c*x)/(pi*x^3) - 1/3*(pi
 + pi*c^2*x^2)^(3/2)*a/(pi*x^3)

________________________________________________________________________________________

Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 217 vs. \(2 (50) = 100\).
time = 0.38, size = 217, normalized size = 3.50 \begin {gather*} -\frac {2 \, \sqrt {\pi + \pi c^{2} x^{2}} {\left (b c^{4} x^{4} + 2 \, b c^{2} x^{2} + b\right )} \log \left (c x + \sqrt {c^{2} x^{2} + 1}\right ) - \sqrt {\pi } {\left (b c^{5} x^{5} + b c^{3} x^{3}\right )} \log \left (\frac {\pi + \pi c^{2} x^{6} + \pi c^{2} x^{2} + \pi x^{4} + \sqrt {\pi } \sqrt {\pi + \pi c^{2} x^{2}} \sqrt {c^{2} x^{2} + 1} {\left (x^{4} - 1\right )}}{c^{2} x^{4} + x^{2}}\right ) + \sqrt {\pi + \pi c^{2} x^{2}} {\left (2 \, a c^{4} x^{4} + 4 \, a c^{2} x^{2} - {\left (b c x^{3} - b c x\right )} \sqrt {c^{2} x^{2} + 1} + 2 \, a\right )}}{6 \, {\left (c^{2} x^{5} + x^{3}\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*arcsinh(c*x))*(pi*c^2*x^2+pi)^(1/2)/x^4,x, algorithm="fricas")

[Out]

-1/6*(2*sqrt(pi + pi*c^2*x^2)*(b*c^4*x^4 + 2*b*c^2*x^2 + b)*log(c*x + sqrt(c^2*x^2 + 1)) - sqrt(pi)*(b*c^5*x^5
 + b*c^3*x^3)*log((pi + pi*c^2*x^6 + pi*c^2*x^2 + pi*x^4 + sqrt(pi)*sqrt(pi + pi*c^2*x^2)*sqrt(c^2*x^2 + 1)*(x
^4 - 1))/(c^2*x^4 + x^2)) + sqrt(pi + pi*c^2*x^2)*(2*a*c^4*x^4 + 4*a*c^2*x^2 - (b*c*x^3 - b*c*x)*sqrt(c^2*x^2
+ 1) + 2*a))/(c^2*x^5 + x^3)

________________________________________________________________________________________

Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \sqrt {\pi } \left (\int \frac {a \sqrt {c^{2} x^{2} + 1}}{x^{4}}\, dx + \int \frac {b \sqrt {c^{2} x^{2} + 1} \operatorname {asinh}{\left (c x \right )}}{x^{4}}\, dx\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*asinh(c*x))*(pi*c**2*x**2+pi)**(1/2)/x**4,x)

[Out]

sqrt(pi)*(Integral(a*sqrt(c**2*x**2 + 1)/x**4, x) + Integral(b*sqrt(c**2*x**2 + 1)*asinh(c*x)/x**4, x))

________________________________________________________________________________________

Giac [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: TypeError} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*arcsinh(c*x))*(pi*c^2*x^2+pi)^(1/2)/x^4,x, algorithm="giac")

[Out]

Exception raised: TypeError >> An error occurred running a Giac command:INPUT:sage2:=int(sage0,sageVARx):;OUTP
UT:sym2poly/r2sym(const gen & e,const index_m & i,const vecteur & l) Error: Bad Argument Value

________________________________________________________________________________________

Mupad [F]
time = 0.00, size = -1, normalized size = -0.02 \begin {gather*} \int \frac {\left (a+b\,\mathrm {asinh}\left (c\,x\right )\right )\,\sqrt {\Pi \,c^2\,x^2+\Pi }}{x^4} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((a + b*asinh(c*x))*(Pi + Pi*c^2*x^2)^(1/2))/x^4,x)

[Out]

int(((a + b*asinh(c*x))*(Pi + Pi*c^2*x^2)^(1/2))/x^4, x)

________________________________________________________________________________________